The force exerted by the ball on the hand can be calculated using the formula derived from Newton's second law of motion, which is , where is the force, represents the change in momentum, and is the time over which this change occurs.

The change in momentum, , can be calculated as the difference between the final momentum, , and the initial momentum, . In this scenario, because the ball comes to a stop in the player's hand, its final velocity (and hence, its final momentum) is 0 . Therefore, the change in momentum is equal to the initial momentum of the ball (since final momentum is zero).

The initial momentum, , of the ball can be calculated using the formula , where is the mass of the ball and is its velocity. Given that the mass of the ball is (converting grams to kilograms) and its velocity is , we have:

Since the change in momentum, , equals the initial momentum ( ) because the final momentum is 0, the force exerted can be found by substituting and into the first formula:

Therefore, the magnitude of force exerted by the ball on the hand of the player is 30 N, which corresponds to Option C.